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Marina CMI [18]
4 years ago
7

What is the only force that acts on a falling body when it is in free fall

Chemistry
2 answers:
olga55 [171]4 years ago
5 0

As learned in an earlier unit, free fall is a special type of motion in which the only force acting upon an object is gravity. Objects that are said to be undergoing free fall, are not encountering a significant force of air resistance; they are falling under the sole influence of gravity.

Leya [2.2K]4 years ago
3 0
I’m pretty sure the only force pulling on a free falling body is gravity. Since gravity pulls things down to earth, the only way that the body can be falling “down to earth” is by gravity.
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Is this right ? I’m stuck on the Explanation part .
Alex777 [14]

Answer:

Lots of things here

Explanation:

Ammonia structure is written as NH3

carbon monoxide is CO

make bonds between O2, so there is 2 oxygen atoms per group,

anything with multiple elements bonded is a compound, thus your answer for carnon monoxide isnt correct, it should be CO for written and it is a compound. Fix your formula for ammonia and also max a bond between those two oxygens because it is O2 not O,

Your structure for SO2 is improper aswell, there are only 3 elements in this molecule, and usually the one out in front of the molecule is the central atom (except hydrogen). So it would go O-S-O for the structure, with only two bonding groups.

4 0
4 years ago
The formula for water is H20. What does the formula H2O tell us about the composition<br> of water?
Llana [10]
H2O is the chemical formula of water. It means that each molecule of water is made up of two hydrogen atoms, indicated by the letter H, and a single oxygen atom, represented by the O. Water is a chemical substance with no smell, taste, or color.
4 0
3 years ago
A heat pump is used to heat a house in the winter and to cool it in the summer. During the winter, the outside air serves as a l
elixir [45]

Answer:

T_{C} = -4.2°C

T_{H} = 49.4°C

Explanation:

A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:

|\frac{Q_{C} }{Q_{H} }| = \frac{T_{C} }{T_{H} }

Similarly,

|Q_{H}| = |Q_{C}| + |W_{S}|

During winter, the value of |T_{H}| = 20°C = 273.15 + 20 = 293.15 K and |W_{S}| = 1.5 kW. Therefore,

|Q_{H}| = 0.75(T_{H} -  T_{C})

Similarly,

|\frac{W_{S} }{Q_{H} }| = 1 - \frac{T_{C} }{T_{H} }

1.5/0.75*(293.15-T_{C}) = 1 - (T_{C}/293.15

Further simplification,

T_{C} = -4.2°C

During summer, T_{C} = 25°C = 273.15+25 = 298.15 K, and |W_{S}| = 1.5 kW. Therefore,

|Q_{C}| = 0.75(T_{H} -  T_{C})

Similarly,

|\frac{W_{S} }{Q_{C} }| = \frac{T_{H} }{T_{C} } - 1

1.5/0.75*(T_{H} - 298.15) = (T_{H}/298.15

Further simplification,

T_{H} = 49.4°C

4 0
4 years ago
An experiment requires that each student use an 8.5 cm length of magnesium ribbon. How many students can do the experiment if th
melisa1 [442]
570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students
7 0
3 years ago
Read 2 more answers
Please help also some of them may be multiple choice, thank you.
Maurinko [17]

Answer: what are the answers to the questions

Explanation:

5 0
3 years ago
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