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Papessa [141]
3 years ago
9

List results of Chemical Reactions.

Chemistry
1 answer:
sweet [91]3 years ago
4 0

Answer:

eating

Explanation:

because when any food or anything that touches your saliva (spit) automatically a chemical reaction!

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Which of the following pairs of atoms would exhibit ionic bonding?
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Its strontium and oxygen.
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Write a summary paragraph explaining limiting and excess reactants and how you can tell which is which.
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In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed. The limiting reactant or limiting reagent is the first reactant to get used up in a chemical reaction. Once the limiting reactant gets used up, the reaction has to stop and cannot continue and there is extra of the other reactants left over. Those are called the excess reactants. The reactant that produces a lesser amount of product is the limiting reagent. The reactant that produces a larger amount of product is the excess reagent. To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
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2 years ago
Standard: PKS2
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3 years ago
Atoms of oxygen have a total of 8 electrons. Are these atoms stable, and why or why not? a.) Yes, because the Octet Rule says st
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8 0
3 years ago
The atomic radius of a gold atom is 144×10^-12. The volume of a gold atom can be calculated using the volume of a sphere. The de
Alekssandra [29.7K]
Given:
Atomic radius of gold = 144 x 10⁻¹² m = 144 pm 
Density of gold = 19.3 g/cm³ = 19.3 x 10⁻³ kg/cm³
Mass of gold sample = 1.40 g = 1.4 x 10⁻³ kg

Calculate the volume of an atom. 
v = [(4π)/3]*(144 x 10⁻¹² m)³ = 1.2508 x 10⁻²⁹ m³

Calculate the mass of an atom.
m=(1.2508\tmes10^{-29}\,m^{3})*(19.3\times 10^{-3}\, \frac{kg}{cm^{3}} )*(10^{2}\, \frac{cm}{m})^{3} \\ = 2.4142 \times 10^{-25}  \, kg

Calculate the number of atoms in a sample of mass 1.40 g.
N =  \frac{1.40 \time 10^{-3} kg}{2.4142 \times 10^{-25} \,  \frac{kg}{atom} } =5.8 \times 10^{21} \, atoms

Answer:  5.8 x 10²¹ atoms
3 0
3 years ago
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