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2 years ago

25° У x 120° y = [ ? ] Enter

Mathematics

2 answers:

Mkey [24]2 years ago

6 0

9514 1404 393

Answer:

y = 95°

x = 60°

Step-by-step explanation:

The applicable theorem is the one that says the exterior angle (120°) is the sum of the remote interior angles:

120° = 25° +y

95° = y . . . . . . . . . . subtract 25° from both sides

_____

If you like, you can get there by calculating x (or not):

x = 180° -120°

y = 180° -25° -x = 180° -25° -(180° -120°)

y = 120° -25° . . . . . simplify — notice we didn't actually have to compute x

Alex2 years ago

5 0

95 degrees

you do 180-120 and get 60 and then add 60 and 25 together and that is 85. then u do 180-85 and get 95

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What is the least common denominator of 2/6 and 7/8

Olegator [25]

Answer:

Therefore the least common denominator is 24.

Step-by-step explanation:

2/6 = 8/24

7/8 = 21/24

No more explanation.

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1 year ago

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Whats the sum of 3/8 and 1/16 a 1/6 b 4/24 c 7/16 d 1/4

Andreyy89

3/8 + 1/16= 7/16
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3 years ago

Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco

chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

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3 years ago

I need help with this one pls!

Alex73 [517]

Hi there!

$\large\boxed{b = \frac{a}{ac - 1}}$

We can begin by making each fraction have a common denominator:

If we make each have a common denominator of ab, we get:

$\frac{b}{ab} + \frac{a}{ab} = c$

Simplify:

$\frac{a + b}{ab} = c$

Multiply both sides by ab:

$a + b = cab$

Move b to the opposite side:

$a = cab - b$

Factor out b:

$a = b(ac - 1)$

Divide by (ac - 1):

$\frac{a}{ac - 1} = b$

4 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago