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Mama L [17]
3 years ago
11

Please help, thanks!

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

(1+2x) + (29+x) =180°

=1+2x+29+x=180°

3x+30=180°

3x=180-30

x= 150/3

x=50

the value of x is 50

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Sports clubs have increasingly been acknowledged as important settings for health promotion. The term sport club is synonymous w
viktelen [127]

The linear equation that represent the left balance of sanjaya’s y after visiting x number of days is:

y = 10x + 500.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

From the data given, we have that:

  • The y-intercept is of 500.
  • The slope is of 10.

Hence the balance is given as follows:

y = 10x + 500.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

7 0
1 year ago
Does (7, 8) make the equation y = x + 5 true?
NNADVOKAT [17]

Answer:

..

Step-by-step explanation:

no the correct point would be (7,12)

7x1=7

7+5=12

3 0
3 years ago
Read 2 more answers
What is the sum of 4z -5y + z + y? Represent the sum by beginning with the z term of your sum. DO NOT INCLUDE SPACES.​
docker41 [41]

Answer:

-4y+5z

Step-by-step explanation:

8 0
3 years ago
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
F(x)=3x and g(x)=x+2 find fog(x),gof(x),fog(2),gof(2)
Gala2k [10]

Answer:

Step-by-step explanation:

fog(x)=f(g(x)) =f(x+2) =3⋅(x+2) =3x+6

gof(x)=g(f(x))=g(3x) =3x+2

gof(2)=3⋅2+2 =6+2 =8

fog(2)=3⋅(2+2) =3*2+6=12

8 0
3 years ago
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