Find the slope of (-3, 2) and (1, 0) plzzzzzz help me

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

3 0

Answer:

m= -1/2

Step-by-step explanation:

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VladimirAG [237]

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5 0

2 years ago

Which of the following is the number of sides for a regular polygon that will not form a regular tessellation?

trasher [3.6K]

Answer with explanation:

A regular polygon is simple closed geometrical shape, only made up of line segments.

And Regular Tessellation, is geometrical shape, made up of regular polygons having, 3 ,or 4 or 6 sides.

It is combination of, only single kind of polygon,either, polygon having 3 sides, or ,4 sides or 6 sides.

→Regular polygon having 3 sides is Called Equilateral Triangle.

→Regular polygon having 4 sides is Called Square.

→Regular polygon having 6 sides is Called Regular Hexagon.

⇒Regular polygon having , 8 sides will not form a regular tessellation.

Option D

6 0

2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$