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adoni [48]
3 years ago
10

Please answer the 33 3/4 one i need answer

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0
33.75
that's the answer I got let me know if you need more help(:
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A circle with a radius of 10,20 or 4 inches has a central angle of 0.25 radians that intercepts an arc of 25,5 or 16 inches
WARRIOR [948]
The radius would be 10 and the arc would be 5.
I hope this helps.
Have a blessed day!
7 0
2 years ago
Y= x-8<br> y= 8 +x<br> What is the solution
tresset_1 [31]

Answer:

x-8=8-x

x=8

y=8-8

y=0

Step-by-step explanation:

y=0

x=8

8 0
3 years ago
Read 2 more answers
What's is the square root of 63
QveST [7]
You want to be finding out what two factors (where one of them is a perfect square) has the produce of 63. It seems like 9 x 7 (9 is the perfect square) works.

\sqrt{63} =  \sqrt{9 \times 7} = \sqrt{9} \times \sqrt{7}

The square root of 9 is 3 so we can just have 3 \sqrt{7} (which just means 3 times the square root of 7). 

3 0
3 years ago
The International Space Station orbits at an altitude of about 250 miles about Earth’s surface. The radius of Earth is approxima
Hatshy [7]
In this case we are dealing with the pythagorean theorm involving right angled triangles. This theorm states that a^2 + b^2 = c^2 which means the square of the hypotenuse (side c, opposite the right angle) is equal to the square of the remaining two sides.

In this case we will say that a = 3963 miles which is the radius of the earth. c is equal to the radius of the earth plus the additional altitude of the space station which is 250 miles; therefore, c = 4213 miles. We must now solve for the value b which is equal to how far an astronaut can see to the horizon.

(3963)^2 + b^2 = (4213)^2
b^2 = 2,044,000
b = 1430 miles.

The astronaut can see 1430 miles to the horizon.
8 0
3 years ago
Bagels: six in a bag Apples: eight in a bag Cookies: twelve in a box Juice Boxes: nine in a box Find the least number of package
morpeh [17]
Bagels 6x12=72
apples 8x9=72
cookies 12x6=72
juice 9x8=72

72/4 kids is 18 lunches
7 0
3 years ago
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