Martin charged $10 for every 5 bags
10/5 = 2
Martin charges $2 per bag
He raked 24 bags of leaves
24 x 2 = 48
Martin earned $48 dollars
hope this helps
Missing part of question:
Draw a tape diagram to show how much cake each of the five children received.
Answer:
See attachment
Step-by-step explanation:
Given
![Equal\ Pieces = 6](https://tex.z-dn.net/?f=Equal%5C%20Pieces%20%3D%206)
![Children = 5](https://tex.z-dn.net/?f=Children%20%3D%205)
Required
Tape diagram to represent the scenario
Because one child is not hungry, the number of children to share the cake becomes 6.
So, first we calculate the share of each child.
![Share = \frac{Pieces}{Children}](https://tex.z-dn.net/?f=Share%20%3D%20%5Cfrac%7BPieces%7D%7BChildren%7D)
![Share = \frac{6}{5}](https://tex.z-dn.net/?f=Share%20%3D%20%5Cfrac%7B6%7D%7B5%7D)
![Share = 1.2](https://tex.z-dn.net/?f=Share%20%3D%201.2)
See attachment for tape diagram
The tape diagram implies that:
![5 * 1.2 = 6](https://tex.z-dn.net/?f=5%20%2A%201.2%20%3D%206)
or
![\frac{6}{1.2} = 5](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B1.2%7D%20%3D%205)
or
![\frac{6}{5} = 1.2](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B5%7D%20%3D%201.2)
Step 1
Revenue (sometimes referred to as sales revenue) is the amount of gross income produced through sales of products or services. This, in the context of the question, means that the revenue generated from the sales of tickets is given by the function below. We are now required to find the price that tickets will be sold at in a day based on the function that will make the revenue to be equal to $0.
The revenue is given by the function;
![\begin{gathered} f(p)=150p-5p^2 \\ f(p)\text{ is the revenue and should be equal to 0 according to the question.} \\ p=\text{ The price of tickets for the day for the revenue to be 0} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%28p%29%3D150p-5p%5E2%20%5C%5C%20f%28p%29%5Ctext%7B%20is%20the%20revenue%20and%20should%20be%20equal%20to%200%20according%20to%20the%20question.%7D%20%5C%5C%20p%3D%5Ctext%7B%20The%20price%20of%20tickets%20for%20the%20day%20for%20the%20revenue%20to%20be%200%7D%20%5Cend%7Bgathered%7D)
To solve this problem or to find this price at which tickets will be solved to give us zero revenue, we must equate the given function for the revenue to 0 and find the value of p, the price of the tickets that make the function to be equal to 0.
For the theatre to make $0 in revenue, this means f(p)=0.
Therefore, we will equate f(p) to 0
Step 2
Equate f(p) to 0
![\begin{gathered} 0=150p-5p^2 \\ p(150-5p)=0----(\text{factorize)} \\ p=0 \\ 0r \\ 150-5p=0 \\ 150=5p \\ \frac{5p}{5}=\frac{150}{5} \\ p=30 \\ p=0\text{ or 30} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%200%3D150p-5p%5E2%20%5C%5C%20p%28150-5p%29%3D0----%28%5Ctext%7Bfactorize%29%7D%20%5C%5C%20p%3D0%20%5C%5C%200r%20%5C%5C%20150-5p%3D0%20%5C%5C%20150%3D5p%20%5C%5C%20%5Cfrac%7B5p%7D%7B5%7D%3D%5Cfrac%7B150%7D%7B5%7D%20%5C%5C%20p%3D30%20%5C%5C%20p%3D0%5Ctext%7B%20or%2030%7D%20%5Cend%7Bgathered%7D)
Therefore the revenue to be zero, the price of the ticket will be $0 or $30 but the question asked us how high the ticket price will be to get a revenue of 0. Both 0 and 30 gave us revenue of 0 but $30 is higher therefore, the answer will be $30.
Check;
![\begin{gathered} 150p-p^2=0 \\ \text{If the price of tickets=0} \\ 150(0)-5(0^2)=0 \\ \text{If p=30} \\ 150(30)-5(30^2)=4500-4500=0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20150p-p%5E2%3D0%20%5C%5C%20%5Ctext%7BIf%20the%20price%20of%20tickets%3D0%7D%20%5C%5C%20150%280%29-5%280%5E2%29%3D0%20%5C%5C%20%5Ctext%7BIf%20p%3D30%7D%20%5C%5C%20150%2830%29-5%2830%5E2%29%3D4500-4500%3D0%20%5Cend%7Bgathered%7D)
Both give us 0 revenue but $30 is higher and the right answer.
Step 3
The equation you can write for revenue of $700 is;
Answer:
11 yd
Step-by-step explanation:
44/4 = 11
A square has four equal sides so you divide the perimeter by four to get your answer of 11
I’m pretty sure it’s w^25