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Jobisdone [24]
3 years ago
6

294 is equal to the quotient of f and 373 Write the sentence as an equation

Mathematics
1 answer:
Bond [772]3 years ago
6 0

Answer:

f/373 = 294

Step-by-step explanation:

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Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

5 0
3 years ago
Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2.5 over 5 and 59 hundredths. Triangles XYZ
adell [148]

Dilation involves changing the size of a shape

<h3>How to determine the relationship between the trigonometry ratios</h3>

From the question, we understand that:

The dilation of triangle XYZ gives triangle ACB

This means that, the following are corresponding points

  • Points X and A
  • Points Y and C
  • Points Z and B

The above means that:

The relationships between the trigonometry ratios of both triangles are:

cos(X) = cos(A), cos(Y) = cos(C) and cos(Z) = cos(B)

<h3>How to determine the measures of segments AC and AB</h3>

In (a), segments XY and XZ corresponds to the segments AC and AB

So, the product of the lengths of XY and XZ and the scale factor will result in the lengths of AC and AB,

i.e.

AC = 2 * XY and AB = 2 * XZ

Read more about dilation at:

brainly.com/question/26332230

5 0
2 years ago
A child building a tower with Blocks uses 15 for the bottom row. Each row has 2 fewer blocks than the previous row. What formula
xenn [34]

Answer:

B)blocks in 5th row=15+(5-1)(-2)

Step-by-step explanation:

We are given that

Number of block in bottom row=15

Each row has 2 fewer blocks than the previous row

We have to find the formula would you use to find the number of blocks in the 5th row.

Number of blocks in  second row=15-2=15+1(-2)

Number of blocks in third row=15-2-2=15+2(-2)

Number of blocks in 4th row=15-2-2-2=15+3(-2)

Number of blocks in 5th row=15-2-2-2-2=15+4(-2)

Therefore, number of block in 5th row

15+(5-1)(-2)

This is required formula to find the number of blocks in the 5th row

Hence, option B is true.

B)blocks in 5th row=15+(5-1)(-2)

4 0
2 years ago
I wil vote barinliest!! Plzz hurry as fast as possible...
crimeas [40]

Answer:

-1 , -0.5

Step-by-step explanation:

Edg

4 0
2 years ago
Read 2 more answers
I need help quickly please have clear explanation and answer written in brainly
Andrei [34K]

Answer:

ii

Step-by-step explanation:

i

4 0
2 years ago
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