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alekssr [168]
3 years ago
5

I really need help with this

Mathematics
2 answers:
trasher [3.6K]3 years ago
5 0
Negative nonlinear and positive association
Komok [63]3 years ago
3 0

Answer: positive assciation

Step-by-step explanation:

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Evaluate fraction numerator d over denominator d x end fraction open parentheses integral subscript 3 superscript x s e c (t )sp
velikii [3]

Answer:

  sec(x)tan(x)

Step-by-step explanation:

This is a direct application of the <em>fundamental theorem of calculus</em>, which tells you ...

  \displaystyle\frac{d}{dx}\int^x_a {f(t)} \, dt=f(x)

Here, f(t) = sec(t)tan(t) and a=3. So, the derivative is ...

  f(x) = sec(x)tan(x)

5 0
4 years ago
Whats 1784 rounded off
lukranit [14]

Answer:

1780 is the best answer

Step-by-step explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE let

7 0
2 years ago
Read 2 more answers
Two less than 5 times a number is the same as the number plus 6
Alex777 [14]

Answer:

3

Step-by-step explanation:

from the question,you get an expresion of

6n-5= n + 10

5n = 15

Isolate n

5n/5 = 15/5

n+3

6 0
4 years ago
What is the length of AB? please help!
ira [324]

Answer:

AB = 12

Step-by-step explanation:

Since the triangle is isosceles, the sides AB and BC are congruent. Then you have ...

4x = 2x+6

2x = 6 . . . . . . subtract 2x

4x = 12 . . . . . .multiply by 2

The side AB has length 12.

3 0
4 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
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