How many different ways can a race with 4 runners be completed? (Assume there is no tie.)
1 answer:
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Answer:
The roots are:
and 
Explanation:
First, we will need to expand the bracket on the left and then put teh equation i standard form which is:
ax² + bx + c = 0
This can be done as follows:
(x+5)² = 10
(x)² + 2(x)(5) + (5)² = 10
x² + 10x + 25 - 10 = 0
x² + 10x + 15 = 0
By comparison, we can find that:
a = 1
b = 10
c = 15
Now to get the roots, we would need to use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)
The roots are:
Explanation:
First, we will need to expand the bracket on the left and then put teh equation i standard form which is:
ax² + bx + c = 0
This can be done as follows:
(x+5)² = 10
(x)² + 2(x)(5) + (5)² = 10
x² + 10x + 25 - 10 = 0
x² + 10x + 15 = 0
By comparison, we can find that:
a = 1
b = 10
c = 15
Now to get the roots, we would need to use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =
or x =
Hope this helps :)