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3 years ago

HELP PLEASE ITS NIGHT HERE IM STUCKK

Mathematics

1 answer:

hjlf3 years ago

5 0

Because it's a multiplication, we can choose this:

72=8x9

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Only smart bros know the answer

Cloud [144]

Answer:

3.3

Step-by-step explanation:

4 x 3 = 12

40 ÷ 12 = 3.3 hope this help . if im wrong oh well

5 0

2 years ago

jennifer walks 8 miles in the same time she can jog 13 miles. if her jogging speed is 8mph faster than her walking speed, how fa

Elanso [62]

Answer:

12.8mph

Step-by-step explanation:

Let 'w' represent her walking speed

->if her jogging speed is 8mph faster than her walking speed

Jogging speed= w+8

Using the time equation i.e time = dist/speed

For walking when distance is 8miles

time = dist / speed= 8/w hrs

For jogging when distance is 13miles

time = dist / speed= 13/(w+8) hrs

Equating the time

jog time = walk time

13/(w+8) = 8/w

By cross multiplying it

13w = 8w + 64

5w = 64

w=64/5

w=12.8mph

Therefore, 12.8mph is her walking speed.

5 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$