Answer:
Step-by-step explanation:
ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.
Similar triangles so we can do
.
Solve for it we get 44y = 6x
Differentiate relative to time t, we get 44y' = 6x'.
change in x (x') is equal to 5. And we get the answer y' =
.
the
ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.
Answer:
Simple column method
Step-by-step explanation:
11
x <u>13</u>
33
<u>110</u>
143
Answer:
15
Step-by-step explanation:
8+8 would be the doubles and that would equal 16.
Then take one away from 16 and that would equal 15
Answer:
64.8
Step-by-step explanation:
Pythagoreon Theroem
a^2 + b^2 = c^2 in this situation it would actually be the opposite, seeing where the "x" is (on a leg) c^2 - b^2 = a^2. First take the square of 67 and 17
67 squared is 4489 and 17 squared is 289 then subtract both results
4489-289 = 4200 take the square root of this number
64.8074 (Round to the tenths 64.8)
Answer:
B: 11 minutes.
Step-by-step explanation:
So, we know that the machine prints at a constant rate.
After 3 minutes, the machine prints 108 posters.
So, let’s find the <em>unit rate. </em>We will divide the output over the input. So:

So, the unit rate of the machine is 36 posters per minute.
We can write an equation. If t represent the number of minutes and p represent the amount of posters, then:

Gives the amount of posters p and t minutes.
We want to know how long it will take Jeffrey to make 396 posters.
So, we can substitute 396 for p and solve for t. Hence:

Divide both sides by 36:

Therefore, it will take Jeffrey 11 minutes to make 396 posters.