Question

Solve the system of equations: y=2x+1. y=x^2+2x-8

Answer 1

Answer:

(- 3, - 5 ) , (3, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 1 → (1)

y = x² + 2x - 8 → (2)

Substitute y = x² + 2x - 8 into (1)

x² + 2x - 8 = 2x + 1 ( subtract 2x + 1 from both sides )

x² - 9 = 0 ( add 9 to both sides )

x² = 9 ( take the square root of both sides )

x = ± $\sqrt{9}$ = ± 3

Substitute these values into (1) for corresponding values of y

x = - 3 : y = 2(- 3) + 1 = - 6 + 1 = - 5 ⇒ (- 3, - 5 )

x = 3 : y = 2(3) + 1 = 6 + 1 = 7 ⇒ (3, 7 )

Answer 2

Answer:

Step-by-step explanation: