Okay lets create an eqn from that information

A first int, B second int, C third int, D fourth int.

B = A + 2
C = A + 4
D = A + 6
A is the smallest integer

B + D = 0.5 (A + C)

Now lets substitute

(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist

2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6

B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0

Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4

Correct
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0

8 0

3 years ago

A circle has a radius of 3 cm. How does the circumference of the circle compare to the area? Drag and drop a phrase to correctly

Lilit [14]

The circumference is about 3.14 ( $\pi$ ) times bigger than twice the radius. Mathematically, this can be writted as $C = 2 \pi r$ , where C equals the circumference and r equals the radius, or $C = \pi d$ where C equals the circumference and d equals the radius.

3 0

2 years ago