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sesenic [268]
3 years ago
6

Pedro is saving part of his allowance to buy a gift for his teacher. At the end of 10 weeks he has saved $95.50 . Pedro saved th

e same amount of money each week. How much did Pedro save each week?
Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

Pedro saves $9.55 each week.

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Need help asap plz ​
stepladder [879]

Answer:

Step-by-step explanation:

1.

sum > 8 or 9,10,11,12

events sum >8 are 36,45,54,63,46,55,64,56,65,66

no. of events=10

p=10/36=5/18

2.

P=291/2237

3.

p=\frac{1}{8}*\frac{4}{8}=\frac{1}{16}

4.

a.

P=5/246

b.

p=208/246=104/123

5.

             yes     no       total

student   56     42         98

teacher     3        7         10

total         59     49        108

8 0
3 years ago
Will mark brainliest to whoever answers correctly first!!!
IgorLugansk [536]
To find the volume, you do area multiplied by thickness( or height)
In this example, you do (1/2*9*6)*10 which is 270
hope I helped ;)
7 0
3 years ago
write each ratio statement as a fraction and reduce to lowest terms if possible.(i)18 to 24 (ii)5 to 15 (iii)14:42 (iv) 15 cents
ArbitrLikvidat [17]

Answer:

i) 3/4

ii) 1/3

iii) 1/3

iv) 5/6 cents

Step-by-step explanation:

Any ratio can be written as a fraction.

For example 3:4 can be writen as 3/4 or 14:42 as 14/42.

After you convert them to fractions you then simplify them by finding their highest common factor (HCF) and then divide both numerator and denominator by the HCF. When you cant simplify the fraction anymore, that is the fraction in its lowest terms.

4 0
3 years ago
Brainliest and Five Stars for correct answers
wel
\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}}
\\\\\\
\lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18
3 0
3 years ago
What’s the equation in vertex form?
pshichka [43]

Answer:

\large\boxed{y=(x+5)^2-64}

Step-by-step explanation:

\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have the equation:}\ y=x^2+10x-39\to x=1,\ b=10,\ c=-39.\\\\\text{Substitute:}\\\\h=\dfrac{-10}{2(1)}=\dfrac{-10}{2}=-5\\\\k=f(-5)=(-5)^2+10(-5)-39=25-50-39=-64\\\\\text{Finally:}\\\\y=1(x-(-5))^2-64=(x+5)^2-64

8 0
3 years ago
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