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maks197457 [2]
4 years ago
11

A physically active adult weighing 185 pounds needs to consume about 2830 calories per day in order to maintain his or her weigh

t. A nutritionist recommends that no more than 35​% of those calories should come from simple sugars. What is the maximum number of calories per day that should come from simple​ sugars?
Mathematics
1 answer:
Vitek1552 [10]4 years ago
5 0

Answer:

A maximum of 990 calories per day should come from simple sugar.

Step-by-step explanation:

Given:

Calories consumed per day = 2830

A nutritionist recommends that no more than 35​% of those calories should come from simple sugars.

Let the number of calories come from sugar be x;

Hence,

x\leq 35\% \ of \ given \ calories

x \leq \frac{35}{100}\times 2830\\\\x\leq 0.35\times 2830\\\\x\leq 990.5

From above we can say that x should be less than or equal to 990.5 hence we can say x is 990 calories

Hence A maximum of 990 calories per day should come from simple sugar.

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3 years ago
A package of 16 individual bags of Takis cost $12.80. If each bag contains 12 ounces, what is the unit cost per ounce?
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Answer:

$0.067

Step-by-step explanation:

Total cost of 16 bags = $12.80

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weight in 16 bag = 16* 12 ounce = 192 ounce

Thus,

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5 0
3 years ago
Alecia builds a box in the shape of a cube with an open top. She plans to paint the box. Alecia calculates that there are 256 sq
STALIN [3.7K]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the options to select the required condition from were not listed. So, I will answer on general terms

From the question, we understand that the cube has an open-top and the surface ares is 256 in^2

Let L represents the edge length, the surface area (S) is:

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Substitute 256 for S

256 = 5L^2

Divide both sides by 5

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Take square roots of both sides:

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L=7.16in ---- approximated

The volume of the cube is:

Volume = L^3

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Volume = 366.3573

Volume = 366.36in^3

<em>So, the edge length of the cube is 7.16 inches and the volume is 366.36 cubic inches</em>

<em />

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Read 2 more answers
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