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2 years ago

How would i round 42.42640687 to the nearest foot? Please help

Mathematics

1 answer:

N76 [4]2 years ago

6 0

Answer:

42, or 42.4 is round to the nearest tenth or 42.43 is round to the nearest hundreths

Step-by-step explanation:

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PLEASE HELP ASSAP LIKE NOW Graph the system of equations on graph paper to answer the question.

7nadin3 [17]

Answer:

(-3, -1)

Step-by-step explanation:

Given the system of equation

y=1/3x-2

y=-3x – 12

Since both equations are y values, we will equate then=m to each other as shown;

1/3x - 2 = -3x - 12

x/3 + 3x = -12 + 2

(x+9x)/3 = -10

x+9x = -30

10x = -30

x = -30/10

x = -3

Substitute x = 3 into equation 1;

From 1: y=1/3x-2

y=1/3(3)-2

y = 1 - 2

y = -1

Hence the required solution (x, y) is (-3, -1)

3 0

3 years ago

Luis put out 6 different pies at a picnic at the end of the picnic, he noticed this about the pies: one whole apple pie was eate

Marat540 [252]

Answer:

2 1/4

Step-by-step explanation:

amount left of apple pie = 1 - 3/4 = 1/4

amount left of blackberry pie = 1 - 1/2 = 1/2

amount left of blueberry pie = 1 - 1/8 = 7/8

amount left of cherry pie = 1 - 5/8 = 3/8

amount left of peach pie = 1 - 3/4 = 1/4

add this figures together

1/4 + 1/2 + 7/8 + 3/8 + 1/4

2 4 + 7 + 3 + 2

8

7 0

3 years ago

What is the range in interval notation?

Lera25 [3.4K]

Sorry I don’t know the answer hope you find one bye

4 0

3 years ago

Two boats, A and B, are approaching a port. The distance between the boats is 12 miles. The bearings of the port with respect to

Karo-lina-s [1.5K]

the answer is 12 miles and 2kms

3 0

3 years ago

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago