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forsale [732]
3 years ago
11

PLEASE HELP ITS DUE TODAY!!

Mathematics
1 answer:
nignag [31]3 years ago
7 0

Answer:

a.) 0.671

b.) 0.985

c.) 0.137

Step-by-step explanation:

Ok..this is easy when you do it a specific way....

a.)

You can easily do 5 - 4.329 and it will give you 0.671.

Now you can do 5 - 0.671 and it will give you the answer as 4.329.

And you got your answer.

The missing value for equation a = 0.671.

b.)

You can easily do 1 - 0.015 and it will give you 0.985.

Now you can do 1 - 0.985 and it will give you the answer as 0.015.

And you got your answer.

The missing vaule for equation b = 0.985.

c.)

You can easily do 1 - 0.863 and it will give you 0.137.

Now you can do 1 - 0.137 and it will give you the answer as 0.863.

And you got your answer.

The missing value for equation c = 0.137

All you have to do is subtract the first number they gave you (the top one), with the actual answer the give you (at the bottom)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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Answer:

20

Step-by-step explanation:

Side of the square = hypotenuse of triangle = √(4² + 2²)=√(16 + 4)=√(20)

Area of a square = (side)² = (√20)² = 20 units²

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Gnoma [55]

Answer:

The probability is;

0.0000003645

Step-by-step explanation:

The probability of packages being early p is 90% = 0.9

The probability of packages being late q will be 1-p = 1-0.9 = 0.1

So the probability of 2 out of 10 random late will be subject to Bernoulli approximation of the Binomial theorem

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ahrayia [7]

Answer:

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Step-by-step explanation:

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den301095 [7]

Answer:

  sum(2^(n+1), for n=1 to 6)

Step-by-step explanation:

To answer this question, you need to know two things:

  • what is an expression for the n-th term
  • how many terms are there

__

The series shown is a geometric series with first term 4 and common ratio 8/4 = 2. The generic form of the n-th term is ...

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You can use this form directly in your summation expression, or you can simplify it a bit.

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The value 128 is 2^7, so n+1 = 7, or n=6 for that term

Your summation expression could be ...

  \displaystyle\sum_{n=1}^6{2^{n+1}}

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<em>Additional comment</em>

The n-th term can also be written as 2×2^n.

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