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forsale [732]
3 years ago
11

PLEASE HELP ITS DUE TODAY!!

Mathematics
1 answer:
nignag [31]3 years ago
7 0

Answer:

a.) 0.671

b.) 0.985

c.) 0.137

Step-by-step explanation:

Ok..this is easy when you do it a specific way....

a.)

You can easily do 5 - 4.329 and it will give you 0.671.

Now you can do 5 - 0.671 and it will give you the answer as 4.329.

And you got your answer.

The missing value for equation a = 0.671.

b.)

You can easily do 1 - 0.015 and it will give you 0.985.

Now you can do 1 - 0.985 and it will give you the answer as 0.015.

And you got your answer.

The missing vaule for equation b = 0.985.

c.)

You can easily do 1 - 0.863 and it will give you 0.137.

Now you can do 1 - 0.137 and it will give you the answer as 0.863.

And you got your answer.

The missing value for equation c = 0.137

All you have to do is subtract the first number they gave you (the top one), with the actual answer the give you (at the bottom)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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6 0
3 years ago
Read 2 more answers
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
A box contains four red, three blue, and six green lenses. two lenses are randomly selected from the box. find the probability o
andrew-mc [135]

The probability of getting two red lenses when two are selected will be 2/13.

<h3>What is probability?</h3>

The probability of favorable events to the total number of occurrences.

A box contains four red, three blue, and six green lenses.

Two lenses are randomly selected from the box.

Then the probability of getting two red lenses when two are selected if the first selection is not replaced before the second selection is made will be

The total number of the event will be

Total event = ¹³C₂

Total event = 78

Then the favorable event will be

Favorable event = ⁴C₁ x ³C₁

Favorable event = 4 x 3 = 12

Then we have

P = 12 / 78

P = 2/13

More about the probability link is given below.

brainly.com/question/795909

#SPJ1

6 0
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3 ten thousands 2 thousands *10
Ad libitum [116K]

3 the thousands = 30.000

2 thousands = 2.000

*10 = times ten


30.000 + 2.000 times 10

32.000 * 10

320.000

3 0
3 years ago
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