Question

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

Answer 1

1805kg more.  1000g=1kg so 5000g=5kg then 1810kg-5kg=1805kg

Answer 2

Answer:

1,805 kilograms more.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

First of all, we will convert 5,000 grams to kilograms by dividing 5,000 by 1000 as 1 kg equals 1000 grams.

$\text{5,000 grams}=\frac{5,000}{1,000}\text{ kg}$

$\text{5,000 grams}=5\text{ kg}$

Now, we will subtract 5 kg from 1810 kg.

$1,810\text{ grams}-5\text{ kg}=1,805\text{ kg}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.