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3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

Mathematics

2 answers:

Marina86 [1]3 years ago

8 0

1805kg more. 1000g=1kg so 5000g=5kg then 1810kg-5kg=1805kg

sleet_krkn [62]3 years ago

8 0

Answer:

1,805 kilograms more.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

First of all, we will convert 5,000 grams to kilograms by dividing 5,000 by 1000 as 1 kg equals 1000 grams.

$\text{5,000 grams}=\frac{5,000}{1,000}\text{ kg}$

$\text{5,000 grams}=5\text{ kg}$

Now, we will subtract 5 kg from 1810 kg.

$1,810\text{ grams}-5\text{ kg}=1,805\text{ kg}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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The sum of a number times 8 and 21 is less than -16.

vodka [1.7K]

Hello.

First of all, let the number be t.

8 times t can be written like this:

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Notice that the number is before the variable and the times sign (×) is not there.

We can write it as 8×t, but we usually write it as 8t.

The sum of means we add:

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Now, "less than" is "<" :

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Therefore, the answer is

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prisoha [69]

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3 years ago

A tank and a pail contained a total of 962 ml of water. When 250 ml of water was poured from the pail to the tank, the amount of

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By solving a system of equations, we will see that the pail originally contained 382.9 ml.

<h3>How to write the system of equations?</h3>

First, we need to define the variables, we will use:

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P = amount of water in the pail.

First, we know that the total amount of water is 962 ml, then we have:

P + T = 962 ml.

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Then the system of equations is:

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To solve this, first, we need to isolate one of the variables in one of the equations, I will isolate T in the first one:

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Now we can solve this for P.

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