In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
2 answers:
Answer:
1,805 kilograms more.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
First of all, we will convert 5,000 grams to kilograms by dividing 5,000 by 1000 as 1 kg equals 1000 grams.
Now, we will subtract 5 kg from 1810 kg.
Therefore, the 2010 world-record pumpkin weighs <u>1,805</u> kilograms more than an average-sized pumpkin.
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Answer:
Bryce is wrong in step 1 because he did not distribute 3 over 5/3
Explanation
Given the steps taken by bryce as shown, we are to find where he made an error
Given the expression;
Step 1:Expand the bracket using the distributive law;
8/3 = 3c + 3(5/3)
<em>Simplify</em>
8/3 = 3c + 15/3
Step 2: Subtract 15/3 from both sides
8/3 - 15/3 = 3c+15/3-15/3
(8-15)/3 = 3c
-7/3 = 3c
Step 3: Multiply both sides by 1/3
-7/3 * 1/3 = 3c * 1/3
-7/9 = c
Swap
c = -7/9
From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect