Let's say the length is L, and the width is W
L is one foot more than 2W, so L=1+2W
the area of the rectangle: A=L*W=300
replace L with 1+2W: (1+2W)*W=300 =>2W^2+W-300=0
solve the quadratic equation: (W-12)(2W+25)=0
W=12 or W=-12.5 (impossible)
so the width is 12, and the length is L=1+2*12=25
please refer to this website for how to factor a quadratic equation
http://www.purplemath.com/modules/factquad.htm
First consider (x+c)^2 where c is just a random constant. if we expand this by foil (which is distributive property twice), we get x^2 + 2cx+ c^2. we want to find c^2 and to do that, we can first find c. we can find c by looking at the 2cx term. this term should match with 12x, so therefore 2c = 12 so c = 6. this also implies that c^2 = 36.
note that for this problem i was working backwards which is a very powerful problem solving tool: start with what you want to attain, and then see how you can go from where you are now to get to your destination.
let me know if you have any questions!!!
Answer:
Step-by-step explanation:
1. You see that you want to subtract g from f
2. Since the two equations have a common denominator, you can easily subtract
3. 2x+6 - (
- 8)
4. 2x - + 14 all over 3x
The value of csc theta is 
<h3>How to determine the value</h3>
It is important to note that the ratio for cot is given as;
Cot theta = adjacent/opposite
cosec theta = hypotenuse/opposite
If cot theta = 3/2, then
Adjacent = 3
Opposite = 2
Using Pythagoras theorem, we have
Hypotenuse square = opposite + adjacent square
Cosec theta =
Thus, the value of csc theta is
Learn more about trigonometric ratio here:
brainly.com/question/13276558
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