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3 years ago

What number must be added to both sides of the equation to complete the square ?

1 answer:

7 0

First consider (x+c)^2 where c is just a random constant. if we expand this by foil (which is distributive property twice), we get x^2 + 2cx+ c^2. we want to find c^2 and to do that, we can first find c. we can find c by looking at the 2cx term. this term should match with 12x, so therefore 2c = 12 so c = 6. this also implies that c^2 = 36.
note that for this problem i was working backwards which is a very powerful problem solving tool: start with what you want to attain, and then see how you can go from where you are now to get to your destination.

let me know if you have any questions!!!

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Can someone help please!! i’ll give brainliest

vladimir1956 [14]

Answer: f (-2 -5) f (1 4)

Step-by-step explanation:

8 0

2 years ago

Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)

Anna11 [10]

Answer:

7y + 2x + 34 = 0

Step-by-step explanation:

The gradient for perpendicular, m = -2/7

The formular equation, y - y1 = m(x - x1)

The equation of line through (4, -6) is:

y - (-6) = -2/7(x - 4)

y + 6 = -2x/7 + 8/7

7y + 42 + 2x - 8 = 0

7y + 2x + 34 = 0

6 0

3 years ago

Read 2 more answers

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

What's the answer to this question?

Wewaii [24]

Answer: 10

Step-by-step explanation:

Use Pythagorean theorem!

a^2+b^2=c^2

6^2+8^2=c^2

64+36=c^2

100=c^2

Take the square root of 100 and you get c=10

5 0

2 years ago

Read 2 more answers

Bsolute Value is the distance from

Yanka [14]

Answer:

The negative integers go to the left: , , , and so on. The distance between a number's place on the number line and is called the number's absolute value The absolute value of a number is its distance from 0 on a number line..

Step-by-step explanation:

Negative

I hope this helps :)

6 0

3 years ago