Question

The vertex form of the equation of a parabola is y = 2(x + 3)2 - 5. What is the standard form of the equation?

Answer 1

Hello : 
y = 2(x + 3)² - 5
y = 2(x²+6x+9) -5
y = 2x² +12x +13...(answer : A) y=2x^2+12x+13 )

Answer 2

Answer:

Option (a) is correct.

The standard form the equation $y=2(x+3)^2-5$ is$y=2x^2+12x+13$

Step-by-step explanation:

Given : the vertex form of the  equation of a parabola is $y=2(x+3)^2-5$

We have to write the given equation in standard form and choose the correct from the given options.

Consider the given equation of parabola $y=2(x+3)^2-5$

The standard form of equation of parabola is $y=ax^2+bx+c$

We can obtain the standard form by expanding the square term in the given equation.

Using algebraic identity $(a+b)^2=a^2+b^2+2ab$, we have,

$\Rightarrow y=2(x+3)^2-5$

$\Rightarrow y=2(x^2+3^2+6x)-5$

Solving brackets, we get,

$\Rightarrow y=2x^2+18+12x-5$

Simplify, we get,

$\Rightarrow y=2x^2+12x+13$

Thus, The standard form the equation $y=2(x+3)^2-5$ is$y=2x^2+12x+13$