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sveta [45]
3 years ago
5

The phrase "miles per hour" is an example of a rate of change. What other commonly used rates of change can you think of in ever

yday speech?
I NEED SOMETHING DIFFERENT THAN SPEED PLEASE
Mathematics
1 answer:
damaskus [11]3 years ago
7 0

Maybe fast or quick?

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skelet666 [1.2K]
You have to divide denominator by numerator to find the constant of proportionality.
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Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
Solve equation 3 + p = 8
Dmitriy789 [7]

Answer:

The answer is 5

Step-by-step explanation:

You can do inverse operation which is Subtraction.

8-3 = 5

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borishaifa [10]

Answer:

Triangular prism with a surface area of 144, C

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4 x 3 = 12, 12 divided by 2 ( x 1/2 ) = 6

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3 x 11 = 33

4 x 11 = 44

5 x 11 = 55

12 + 33 + 44 + 55 = 144

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