Question

WILL MAKR BRAINLIEST IF GOTTEN RIGHT

Answer 1

Answer:

hmm give me more so I can answer it

Answer 2

Answer:

$V_{weights} =1,243 \: cm^3$

Step-by-step explanation:

Radius of weight $r_1=\frac{20}{2}= 10 \:cm$

Radius of hole $r_2=\frac{2}{2}= 1 \:cm$

Height of weight as well as hole (h) = 2 cm

Volume of weights = (Volume of one weight - volume of hole)

$\therefore V_{weights} = 2 (\pi r_1^2 h - \pi r_2^2 h)$

$\therefore V_{weights} = 2 \pi (r_1^2 - r_2^2 )h$

$\therefore V_{weights} = 2 (3.14)(10^2 - 1^2 )2$

$\therefore V_{weights} =12.56(100 - 1 )$

$\therefore V_{weights} = 12.56(99)$

$\therefore V_{weights} =1,243.44$

$\therefore V_{weights} \approx 1,243 \: cm^3$