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Andreyy89
3 years ago
13

PLEASE HELP Find the value of x in the triangle shown below.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

82^o

Step-by-step explanation:

74 + 24 = 98

180 - 98 = 82^o

Hope it helps!

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Australia is 2.97 x 106 square
Arlecino [84]

Answer:1.7

Step-by-step explanation:

First you want to multiply 2.97 by 106

2.97 x 106 = 314.82

Now you want to multiply 1.72 by 107

1.72 x 107 = 184.04

Now you want to divide them

314.82 / 184.04 = 1.71

Now you want to round it to the nearest tenth... if a number is 5 or above you round it up but if it is 4 or below your number stays the same

Since 1 is lower than 5 you keep your number the same

<u>1.7</u>

8 0
3 years ago
Q10: A two-dimensional cross section is created by slicing a pyramid parallel to its base.
Maslowich
The correct answer is D
6 0
3 years ago
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
john has 7f five dollar bills. he wants to buy a baseball bat that costs $38. A.how much money does he have? B. does he have eno
elena55 [62]
A. 7 times 5 equals $35

B.No he does not have enough money because he only has $35 and he needs $3 more.
5 0
3 years ago
Factor 12G+4G+4 and<br><br> 40-10h+9-4h
liraira [26]
Hello : 
<span> 12G+4G+4 = 4 (3G +G+1)=4(4G+1)
</span><span>40-10h+9-4h = -14h +49 = -7(2h-7)</span>

4 0
4 years ago
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