Which point is on the graph of a direct variation equation in which k = 0.4?

Ed's car can travel 93.5 miles on 4.25 gallons of gas. How far can the car travel on 1 gallon of gas? A. 2.2 miles B. 4.25 miles

Sav [38]

The answer is C, 22 miles

7 0

3 years ago

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Write an equation in slope intercept form for the line with slope -3 and y-intercept -1

Umnica [9.8K]

Answer:

y = -3x -1

Step-by-step explanation:

Slope intercept form is y=mx+b or y=mx-b

m is the slope (steepness of the line, think of a steep or level mountain)

b is the y-intercept (the place where the line FIRST meets the y-axis a.k.a. the vertical line down the middle of a graph.)

y= -3x -1

means your line is going downhill, and it crosses the y-axis at -1.

If you need any help graphing refer to Desmos Graphing Calcuator (it's free and online.)

<em>If you need me to explain anything, feel free to ask me in the comments. I know mathematics can be worrisome, but I am here to help!</em>

Thanks, buddy

- throckmorton

5 0

2 years ago

The price of apples is $3.60 for 3 pounds write the price as a unit rate

Finger [1]

Take the total and divide by the amount to get answer.

3.60 /3 = $1.20 per pound

4 0

3 years ago

What is the answer to this math question?

oksano4ka [1.4K]

Answer:

The answer is option 3.

Step-by-step explanation:

First we have to find the area of both rectangle and triangle :

Rectangle,

$area = base \times height$

Let base = 9,

Let height = 3,

$area = 9 \times 3 \\ area = 27 \: {m}^{2}$

Triangle,

$area = \frac{1}{2} \times base \times height$

Let base = 3,

Let height = 3,

$area = \frac{1}{2} \times 3 \times 3 \\ area = \frac{1}{2} \times 9 \\ area = \frac{9}{2} \\ area = 4.5 \: {m}^{2}$

Lastly, in order to find the shaded region you have to substract the area of triangle from the area of rectangle :

$area = 27 - 4.5 \\ area = 22.5 \: {m}^{2}$

5 0

3 years ago

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In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee

kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that $x^{2} =pz$

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

$\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}$

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

$\frac{x}{z}= \frac{p}{x}$

Cross multiply

$x^{2}=pz$

Hence proved.

7 0

4 years ago