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DaniilM [7]
3 years ago
8

The class with the largest median for hours spent studying is

Mathematics
1 answer:
musickatia [10]3 years ago
5 0
The average number of jumps is 239, just add all the numbers and divide by the amount of numbers you have. Easy! Hope this helped!
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In general, shopping online is supposed to be more convenient than going to stores. However, according to a recent Harris Intera
Dmitry_Shevchenko [17]

Answer:

a) 13% of people did not experience problems with an online transaction.

b) 36.54% of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website

c) 46.11% of people experienced problems with an online transaction and contacted customer-service representatives.

Step-by-step explanation:

a. What percentage of people did not experience problems with an online transaction?

87% of people have experienced problems with an online transaction. So 100 - 87 = 13% of people did not experience problems with an online transaction.

b. What percentage of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website?

87% of people have experienced problems with an online transaction. Forty-two percent of people who experienced a problem abandoned the transaction or switched to a competitor′s website.

Then:

0.87*0.42 = 0.3654

36.54% of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website.

c. What percentage of people experienced problems with an online transaction and contacted customer-service representatives?

87% of people have experienced problems with an online transaction. Fifty-three percent of people who experienced problems contacted customer-service representatives.

Then:

0.87*0.53 = 0.4611

46.11% of people experienced problems with an online transaction and contacted customer-service representatives.

3 0
3 years ago
What is 1/2 of 7/8? In fraction firm
dimulka [17.4K]

1/2*7/8=7/16

Answer:

7/16

5 0
3 years ago
What is the range of the function?
levacccp [35]
The answer is D. {-2, 2, 3, 4}
5 0
3 years ago
The two shortest sides of a right triangle are 10 in. And 24 in. long. What is the length of the shortest side of a similar righ
ivanzaharov [21]
If the two shortest sides of the triangle are 10in and 24in, then using Pythagoras' theorem, the longest side =
\sqrt{10^2 + 24^2} 
= \sqrt{676}
= 26

Now we know the two longest sides of the first triangle (24in and 26in) we can compare them with the two longest sides of the second triangle.
If x = the scale factor the first triangle is enlarged by then
26x = 39 and 24x = 36 
⇒ x = 1.5

Finally, we need to multiply the smallest side of the first triangle by the scale factor to find the shortest side of the second triangle.
10(1.5) = 15
So the length of the shortest side of the other triangle is 15in.

You could, instead, calculate the length of the shortest side of the second triangle by using Pythagoras' theorem and ignoring the first triangle completely.
5 0
3 years ago
Read 2 more answers
A broken faucet leaks 1 gallon of water every 1 and1/3 months the amount of months that pass m varies directly with the amount o
Simora [160]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \textit{\underline{m} varies directly with the amount of gallons}\implies \stackrel{months}{m}=k\stackrel{gallons}{g}
\\\\\\
\textit{we also know that }
\begin{cases}
m=1\frac{1}{3}\\
\qquad \frac{4}{3}\\
g=1
\end{cases}\implies \cfrac{4}{3}=k1\implies \cfrac{4}{3}=k
\\\\\\
\boxed{m=\cfrac{4}{3}g}\\\\
-------------------------------\\\\
\textit{what's \underline{m} when g=7?}\qquad m=\cfrac{4}{3}\cdot 7\implies m=\cfrac{28}{3}\implies m=9\frac{1}{3}
6 0
3 years ago
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