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DaniilM [7]
2 years ago
8

The class with the largest median for hours spent studying is

Mathematics
1 answer:
musickatia [10]2 years ago
5 0
The average number of jumps is 239, just add all the numbers and divide by the amount of numbers you have. Easy! Hope this helped!
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#1. About 15.
5x3

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2 years ago
12=15(z−51​)<br> What is Z
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Answer:

51.8

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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2 years ago
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andre [41]
Check the picture below.  So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

\bf \textit{hyperbolas, vertical traverse axis }\\\\&#10;\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ({{ h}},{{ k}})\\&#10;vertices\ ({{ h}}, {{ k}}\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{{{ a }}^2+{{ b }}^2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;h=0\\&#10;k=0\\&#10;a=4\\&#10;c=5&#10;\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1&#10;\\\\\\&#10;c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\\\\\\&#10;\sqrt{5^2-4^2}=b\implies \boxed{3=b}&#10;\\\\\\&#10;\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}

7 0
3 years ago
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