Please help I have been stuck for a while now

Please help me, giving brainliest.

emmainna [20.7K]

I'm not sure what you want but the slope for each graph from left to right is 5, -7/8, -2.

The equation of each graph from left to right in slope intercept form is

y = 5x + 2, y = -7/8x - 11/8, y = -2x + 6.

4 0

4 years ago

Solve for a -90=-6a-12

Ahat [919]

Step-by-step explanation:

=>a+6a=90-12

=>7a=78

=>a=11,14

6 0

3 years ago

Read 2 more answers

By the age of 21, the best violinist and pianist will have practiced at least 10,000 hours. If you practice and instrument 45 mi

Alika [10]

Answer:

273.94 hours.

Step-by-step explanation:

1 day = 0.75 hours of practicing in a day.

365.25 = x

1/365.25 = 0.75/x Cross multiply

x = 0.75 * 365.25 Combine

x = 273.94 hours

8 0

3 years ago

What is the length of leg s of the triangle below?

maks197457 [2]

Answer:

What is the length of leg s of the triangle below?

B. atau F

4 0

3 years ago

A cell of some bacteria divides into two cells every 10 minutes.The initial population is 3 bacteria. (a) Find the size of the p

mars1129 [50]

Answer:

(a) $P_{t}=3(2)^{6t}$

(b) $3(2)^{42}$

(c) 28.07 minutes

Step-by-step explanation:

A cell of some bacteria divides itself into 2 cells in every 10 minutes and initial population of the bacteria was 3.

That means sequence formed will be 3, 6, 12, 24............

We can easily say that this sequence is a geometric sequence having common ratio (r) = $\frac{T_{2}}{T_{1}}=\frac{6}{3}$

r = 2

Now we know the explicit formula of a geometric sequence is given by

$P_{t}=P_{0}(r)^{\frac{60t}{10}}=P_{0}(r)^{6t}$

Where a = Initial population = 3 bacteria

r = common ratio = 2

and t = time in hours

So explicit formula will be $P_{t}=3(2)^{6t}$

(a) Now we have to calculate the size of population after t hours

$P_{t}=3(2)^{6t}$

(b) We have to find the size of population after 7 hours or 420 minutes

$P_{t}=3(2)^{6\times7}$

= $3(2)^{42}$

After 7 hours bacteria population will be $3(2)^{42}$

(c) Time to reach population as 21

By the explicit formula

$21=3(2)^{6t}$

$2^{6t}=\frac{21}{3}=7$

Now we take log on both the sides of the equation

$log(2^{6t})=log(7)$

6t log2 = log 7

6t(0.301) = 0.845

t(1.806) = 0.845

t = $\frac{0.845}{1.806}=0.468$ hours

Or t = 0.468×60 = 28.07 minutes

Therefore, after 28.07 minutes bacterial population will be 21

5 0

3 years ago