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3 years ago

The figure below consists of a triangle, a rectangle, and a trapezoid.

Mathematics

1 answer:

daser333 [38]3 years ago

3 0

Answer:

I am not sure but I think its 42 reason is multiplication I might be wrong if its an exam or test or quiz dont use this answer

Step-by-step explanation:

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Create a rule to find the nth term. <br> 4096, 2048, 1024, ...

ella [17]

Answer:

n=4096+(n-1)*-2048

Step-by-step explanation:

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2 years ago

Find d and the measure of each side of equilateral triangle KLM if KL=d+2, LM=12-d, and KM=4d-13

fiasKO [112]

Answer:

all sides are 7 units

Step-by-step explanation:

Since the triangle is equilateral then all 3 sides are equal in length

equate any 2 sides and solve for d

KL = LM

d + 2 = 12 - d ( add d to both sides )

2d + 2 = 12 ( subtract 2 from both sides )

2d = 10 ( divide both sides by 2 )

d = 5

KL = d + 2 = 5 + 2 = 7

LM = 12 - d = 12 - 5 = 7

KM = 4d - 13 = (4 × 5) - 13 = 20 - 13 = 7

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3 years ago

Chad stopped and filled the car with 11 gallons of gas. he had driven 308 miles using the previous 11 gallons of gas. how many m

Galina-37 [17]

28 miles per gallon

8 0

3 years ago

What is the area of her garden in square feet?

Murrr4er [49]

Answer:

7.5x6.5=48.75

Step-by-step explanation:

3 0

3 years ago

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If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.

Gnom [1K]

Answer: $\tan \theta=\dfrac{1}{\sqrt3}.$

Step-by-step explanation: Given that

$\sin\theta=-\dfrac{1}{2}$ and $\theta$ lies in Quadrant III.

We are to find the value of $\tan \theta.$

We will be using the following trigonometric identities:

$(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.$

We have

$\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.$

Since $\theta$ lies in Quadrant III, so tangent will be positive.

Thus,

$\tan \theta=\dfrac{1}{\sqrt3}.$

8 0

3 years ago

Read 2 more answers