Samuel is preventing a boulder from rolling down a hill with a slope of 35°. If the boulder
1 answer:
Answer:
1,809.98 lb*m/s^2
Step-by-step explanation:
First, we want to know how much weight of the boulder is projected along the path in which the boulder can move.
The weight of the boulder is:
W = 322lb*9.8 m/s^2 = (3,155.6 lb*m/s^2)
This weight has a direction that is vertical, pointing downwards.
Now, we know that the angle of the hill is 35°
The angle that makes the direction of the weight and this angle, is:
(90° - 35°)
(A rough sketch of this situation can be seen in the image below)
Then we need to project the weight over this direction, and that will be given by:
P = W*cos(90° - 35°) = (3,155.6 lb*m/s^2)*cos(55°) = 1,809.98 lb*m/s^2
This is the force that Samuel needs to exert on the boulder if he wants the boulder to not roll down.
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Hi student, let me help you out! :)
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We are asked to find the equation of the line, using the given information:
, which is the slope
which is a point that the line contains
- The slope is the number before x, in the form
.
Since "m" is the slope, and we're given what the slope is, we can substitute -3 for m:
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Now, we need to find the y intercept, "b", of the line.
Here's how it's done:
Remember the point that the line contains, (1,2)?
Well, its y-coordinate is 2; so what we do is substitute 2 for y:
Also, its x-coordinate is 1, so we substitute 1 for x:
Now, solve for b:
Add 3 to both sides:
Thus, we have
Thus, the equation of the line is:
Hope it helps you out! :D
Ask in comments if any queries arise.
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