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ziro4ka [17]
2 years ago
13

A baseball stadium charges $8 handling fee per ticket. It also charges a single $2.50 handling fee when purchasing 8 or fewer ti

ckets online. Which pair of equations could be used to find the total handling fee, y, in dollars, when purchasing x tickets online?
A. When purchasing 8 or fewer tickets: y = 8x + 2.5
When purchasing more than 8 tickets: y = 8x-2.5

B. When purchasing 8 or fewer tickets: y = 8x + 2.5x
When purchasing more than 8 tickets: y = 8x-2.5x

C.When purchasing 8 or fewer tickets: y = 8x + 2.5x
When purchasing more than 8 tickets: y = 8x

D. When purchasing 8 or fewer tickets: y = 8x + 2.5
When purchasing more than 8 tickets: y = 8x
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
7 0
The expression V85x should be further simplified for which value of x? ... bought, which of the following equations should be used to find y, the total cost of ... Kennel charges $15 per day plus $20 for a processing fee.
32 pages·7 MB
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Find the radius of this circle.<br> A = ar2<br> r = [?] ft<br> A = 9aft?
Sergeu [11.5K]

Answer:

A = \pi . r^2

If A = 9\pift^2

\pi . r^2 = 9\pift^2

r^2 = 9ft^2

r = sqrt(9ft^2)

r = 3ft ( r>0)

Step-by-step explanation:

6 0
2 years ago
In how many ways can we pick three different numbers out of the group
ELEN [110]

i will bite - this is not a complete ans but an approximation:

there are 100*99*98 ways to pick 3 different no. out of 100

if 2 of the no. picked are >10, then there is no way the third no. can be larger than the products of the other 2 nos.

there are 90*89*98 ways to pick 2 nos between 10 and 100 and a third no. between 1 and 100.

So an approximate ans = 100*99*98 - 90*89*98 = 185220 but the actual ans will be smaller than this.



4 0
3 years ago
13x-7y+4x
Vinvika [58]

Answer:

17−7

Step-by-step explanation:

Hope this helped good luck in your work!

4 0
3 years ago
If x+a is a factor of 2x²+2ax+5x+10,find a.
vazorg [7]

If x+a is a factor of the polynomial, it means that -a is a root of the polynomial.

In fact, if a polynomial p(x) has a root x_0 (i.e. p(x_0)=0), then the polynomial is divisible by (x-x_0)

In your case, you know that the polynomial is divisible by (x+a)=(x-(-a)), so -a is a solution.

Let's evaluate p(-a) and set it to zero:

2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2

We can check the answer: if a=2 the polynomial becomes

2x^2+2(2)x+5x+10 = 2x^2+9x+10

And we're claiming that -a=-2 is a root of this polynomial:

2(-2)^2+9(-2)+10 = 2\cdot 4 - 18 + 10 = 0

5 0
3 years ago
Rodger has 47 cars . Can he group the cars in more than two ways?
deff fn [24]
First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
4 0
3 years ago
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