Question

How do you find g(h(n))

Answer 1

Answer:

A -4n^2-2n + 3

Step-by-step explanation:

let's simplify this by making h(n) = u

this means g(h(n)) = g(u)

u = h(n) = -2n^2 - n

g(h(n)) = g(u) = 2u + 3

now plug h(n)) in wherever there is u

2(-2n^2-n)+3

-4n^2-2n + 3