The correct answer is A. Ammonia.
The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave
Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz
Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters
Answer:
the frequency is 18
Explanation:
please mark me as the branlest hope it helps please
the decay of the neutrons in the nucleus of the atom
Phosphorylation is a process in which addition of phosphoryl group is added. This process explains the presence of the PO₃⁻ in the molecules. One type of phosphorylation is that which is termed as the substrate-level phosphorylation. This is a metabolic reaction that allows or results to the formation of ATP due to the direct transfer of phosphoryl to ADP.
Hence, the answer is ATP.
