Answer: pH of the given solution is 8.7.
Explanation:
For the buffer mixture, initial pOH will be given as follows.
pOH =
=
=
= 5.523
When 0.05 mol NaOH is added to this buffer solution then concentration of species present will be as follows.
0.05 mol 0.25 0.75 0
0 0.20 (0.75 + 0.25) 0.05
Hence, the volume of solution will be 1 liter.
[BOH] = , [Salt] =
So, pOH = [/tex]
= 6 - 0.69
= 5.30
Now, we will calculate the pH as follows.
pH = 14 - 5.30
= 8.7
Thus, we can conclude that pH of the given solution is 8.7.
Answer:
The final concentration of KCl is 4%
Explanation:
This is a solution with KCl and water.
12% it's a way of concentration that indicates, that in 100 mL of solution, we have 12 g of solute.
If we add 200 mL to this solution, we also have 12 g of solute but now, we have to calculate the new concentration.
New volume = 100 mL + 200 mL → 300 mL
Let's make a rule of three
In 300 mL we have 12 g of solute
In 100 mL we have (100 .12) / 300 = 4
Answer:
it is a because blood is pumped but heart so the answer is A