Answer:
Anode: H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻
Cathode: 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)
E° = 1.60 V
Explanation:
Let's consider the reaction taking place in a galvanic cell.
2 Fe⁺³(aq) + H₂(g) + 2 OH⁻(aq) → 2 Fe⁺²(aq) + 2 H₂O(l)
The corresponding half-reactions are:
Anode (oxidation): H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻ E°red = - 0.83 V
Cathode (reduction): 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq) E°red = 0.77 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.77 V - (-0.83 V) = 1.60 V
Answer and Explanation:
Explosion of a star releases what into the atmosphere?
This would be many basic elements; Calcium, Oxygen, and Carbon for the most known. These get flung out into space at light speed, which through time evolves into other stars and planets. Though this is not promised always.
Answer:
The oxygen we breathe is not in atomic form. It is in its molecular form, which is two oxygen atoms joined together by bonds, and between its two atoms, this molecule has 16 protons, 16 electrons, and most commonly 16 neutrons. Answer 5: An oxygen atom contains eight protons.
The balanced chemical reaction is:
2Na + Cl2 = 2NaCl
We are given the amount of sodium to be used for the reaction. This will be the starting point of our calculations.
92.0 g Na ( 1 mol Na / 22.99 g Na ) ( 1 mol Cl2 / 2 mol Na ) ( 70.9 g Cl2 / 1 mol Cl2) = 141.86 g Cl2
