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2 years ago

That my last Q8 A , can someone help me with

Chemistry

2 answers:

scoray [572]2 years ago

4 0

The first was louder, while the second had a higher pitch

DENIUS [597]2 years ago

3 0

The first whistle is louder while the second whistle has a higher pitch
Loud vs high

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Two compounds are standing at the same temperature. Compound "A" is evaporating more slowly than compound "B." According to the

frosja888 [35]

Answer:

Option D) Compound B may have a lower molecular weight.

Explanation:

Compound A and B are standing at the same temperature yet compound A is evaporating more slowly than compound B.

This simply indicates that compound B have a lower molecular weight than compound A.

This can further be seen when gasoline and kerosene are placed under same temperature. The gasoline will evaporate faster than kerosene because the molecular weight of the gasoline is low when compared to that of the kerosene.

4 0

3 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0

3 years ago

Question<br> What is the name of the covalent compound with the formula P2N3?

Elina [12.6K]

Answer:

P2N5

Explanation:

you have to plus it 2 times

6 0

2 years ago

6. How many moles are in 25g of potassium?

Ahat [919]

0.6394139898665671 that’s how many moles are in 25g of potassium !

8 0

2 years ago

Hydrogen gas and oxygen gas react to produce water. Both of these gases are present in

bonufazy [111]

Water isn't being produced all around us because the hydrogen and oxygen are present in stable form.

<h3>How come water isn't being produced all around us?</h3>

Water molecule is produced when the unstable hydrogen reacts with unstable oxygen because they are very reactive. Due to their reactive nature, hydrogen and oxygen react with each other forming water molecule. So that's why we can say that water is not being produced around us due to stable form of hydrogen and oxygen.

So we can conclude that Water isn't being produced all around us because the hydrogen and oxygen are present in stable form.

Learn more about water here: brainly.com/question/1313076

#SPJ1

6 0

1 year ago