Answer:
Tilting - Rock strata always form horizontally, so anything not horizontal has been acted upon. ... Folding - If the rocks are bent, they have been folded. Faulting - If there is a break and movement within the rocks, this is a fault.
Explanation:
Most woolly mammoths went extinct roughly 10,000 years ago amid a warming climate and widespread human hunting. But isolated populations survived for thousands of years after that on St. Paul Island in the Bering Sea and Wrangel Island in the Arctic Ocean
There is no vascular cambium between the xylem and phloem in monocot vascular bundles. This means that no wood is produced in the annual ring.
<h3>What are annual rings?</h3>
An annual ring is a band of wood that can be seen in a cross-section of the stem or root of a temperate plant. It represents the annual growth of a plant. It represents a plant's growth over a year. Annual rings form as a result of vascular cambium activity during intrastellar secondary growth.
The study of tree growth rings can be very useful for determining the age of a specimen as well as understanding past hydrological phenomena as well as understanding geomorphological phenomena such as movements or landslides. The study of these rings can also be used to study and reconstruct the past and present climate of a specific area.
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rice=polysaccharide, grapes=monosaccharide, milk=disaccharide
Answer:
See the answer with the explanation below.
Explanation:
Assuming the allele for sickle cell disease is represented by S and the alternate, non-sickle cell version is A; AA would be <em>homozygous normal</em>, AS would be <em>heterozygous normal</em>, and SS would be a <em>sickler</em>.
a. <em>The genotype of the father in the first generation would be </em><em>AS</em>.
The father is heterozygous, since the mother is affected and the couple produced an affected child. The cross can be illustrated thus:
AS (father) x SS (mother) = AS, AS, SS, SS
b. <em>The genotype of the daughter in the second generation would be </em><em>SS</em><em> </em>since she is phenotypically affected for the disease.
c. <em>The genotype of individual 3 in the second generation would be heterozygous, </em><em>AS</em>.
The cross between the the heterozygous normal father and the sickler mother can only produce one of heterozygous normal individuals or sickle cell diseased individuals. Hence, individual 3 has to be heterozygous since he appeared phenotypically normal in the pedigree.
