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3 years ago

The difference of twice a number and 6 is at most 25

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

This is your personal answer
2( x - 6) <= 28

x - 6 <= 14

x <= 20

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Thank you in advance for those who provided support to my question!

alekssr [168]

GCF of 10 and 12 is 2

LCM of 16 and 24 is 48

Added together is 50

5 0

3 years ago

Read 2 more answers

3p + 2q = 14<br> 10p + 6q = 44<br> What is p and what is q

Airida [17]

Answer:

p = 2 ; q = 4

Step-by-step explanation:

Given tbe equation :

3p + 2q = 14 - - - (1)

10p + 6q = 44 - - -(2)

What is p and what is q

This is a simultaneous equation ; using elimination method :

Multiply (1) by 6 and (2) by 2

18p + 12q = 84 - - - - (3)

20p + 12q = 88 - - - (4)

Subtract (3) and (4)

-2p = - 4

p = 4/2

p = 2

Put p = 2 in (1)

3p + 2q = 14

3(2) + 2q = 14

6 + 2q = 14

2q = 14 - 6

2q = 8

q = 8/2

q = 4

p = 2 ; q = 4

4 0

3 years ago

Lesson 3: Revisiting Proportional Relationships

lina2011 [118]

Relationship is going to work out so 72728

8 0

2 years ago

Adding and subtracting the given polynomials

Usimov [2.4K]

You have to combine like terms, so the variable (x, y, s, d, c....) and the exponents must be the same in order to combine them.

For example:

x² + x³ Since they don't have the same exponent, you can't combine them

y² + 3y² = 4y²

23x + x = 24x

4. 2s² + 1 + s² - 2s + 1 You can rearrange it if it makes it easier

2s² + s² - 2s + 1 + 1 = 3s² - 2s + 2

5. 5t² - 2t - 1 - (3t² - 5t + 7) Distribute/multiply the - to (3t² - 5t + 7)

5t² - 2t - 1 - 3t² + 5t - 7 = 2t² + 3t - 8

Do the same for #9 and #10, and you should get:

9. 2k² + 5k - 9

10. 6y³ - 7y² - 6y - 12

3 0

3 years ago

An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus

Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

$\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1$ (1)

Where:

$h, k$ - Coordinates of the center of the ellipse.
$a$ , $b$ - Lengths of each semiaxis.

Hence, the maximum distance ( $d_{max}$ ), in feet, is calculated by this formula:

$d_{max} = 2\cdot b$ (2)

If we know that $b = 17$ , then the maximum distance between any two points of the ellipse is:

$d_{max} = 2\cdot (17\,ft)$

$d_{max} = 34\,ft$

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. $\blacksquare$

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em> $\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1$ <em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

5 0

2 years ago