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Answer:
1. A high level algorithm for cooking a cheeseburger could be:
- Heat fry pan
- Cook one side of the hamburger
- Wait
- Turn hamburger upside down
- Put cheese over hamburger
- Wait
- Cut hamburger bread in half
- Put cooked hamburger inside bread
- End (eat)
2. A detailed algorithm for cooking a cheeseburger could be:
- Place fry pan over the stove heater
- Turn on heater (max temp)
- IF fry pan not hot: wait, else continue
- Place raw hamburger on fry pan
- IF hamburger not half cooked: Wait X time then go to line 5, else continue
- Turn hamburger upside down
- Put N slices of cheese over hamburger
- IF hamburger not fully cooked: Wait X time then go to line 8, else continue
- Turn off heater
- Cut hamburger bread in half horizontally
- Put cooked hamburger on one of the bread halves.
- Put second bread half on top of hamburger
- End (eat)
Explanation:
An algorithm is simply a list of steps to perform a defined action.
On 1, we described the most relevant steps to cook a simple cheeseburger.
Then on point 2, the same steps were taken and expanded with more detailed steps and conditions required to continue executing the following steps.
In computational terms, we used pseudo-code for the algorithm, since this is a list of actions not specific to any programming language.
Also we can say this is a structured programming example due to the sequential nature of the cooking process.
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Answer:
a. (p*Main).age = 20;
Explanation:
Pointers use ->
where as normal variable use . to access its members
pMain is the pointer.
*pMain is the value inside pMain.
pMain->age = 20;
This statement equals to
(*pMain).age = 20;
Answer is option a.
I would go with A) The Internet
I hope that turns out well for you. Good luck! (:
