Answer:

We also know that for Wedneday we have two times tickets for adults compared to child so we have

And using this condition we have:

And solving for X we got:

So then the number of tickets sold for child are 36
Step-by-step explanation:
For this problem we can set upt the following notation
X = number of tickets for child
Y= number of tickets for adults
And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

We also know that for Wedneday we have two times tickets for adults compared to child so we have

And using this condition we have:

And solving for X we got:

So then the number of tickets sold for child are 36
Answer:
Net Profit after tax Rs 15,000
Step-by-step explanation:
The computation of the net profit after tax is shown below:
Gross profit Rs. 1,25,000
Less:
Selling and distribution expenses Rs. 21,000
General and administrative expenses Rs. 75,000
Interest on loan Rs. 5,000
Gain on sale of plant Rs. 4,000
Profit before tax Rs 20,000
Less: income tax expense at 25% of Rs 20,000 Rs 5000
Net Profit after tax Rs 15,000
Answer:
--- 1 over 5 squared
Step-by-step explanation:
When multiplying terms with a common base, you just add the exponents:

That's true even when you don't have any exponents.


A negative exponent isn't fully simplified, so there's another rule to use:

That is '1 over x to the y' if it's too small to read.

Answer:
what's the question???/
Step-by-step explanation:
Answer:
P(t) = 12e^1.3863k
Step-by-step explanation:
The general exponential equation is represented as;
P(t) = P0e^kt
P(t) is the population of the mice after t years
k is the constant
P0 is the initial population of the mice
t is the time in months
If after one month there are 48 population, then;
P(1) = P0e^k(1)
48 = P0e^k ...... 1
Also if after 2 months there are "192" mice, then;
192 = P0e^2k.... 2
Divide equation 2 by 1;
192/48 = P0e^2k/P0e^k
4 = e^2k-k
4 = e^k
Apply ln to both sides
ln4 = lne^k
k = ln4
k = 1.3863
Substitute e^k into equation 1 to get P0
From 1, 48 = P0e^k
48 = 4P0
P0 = 48/4
P0 = 12
Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;
P(t) = 12e^1.3863k
This gives the equation representing the scenario