Answer:256
Step-by-step explanation:
-160×8/-5=x
X=256
Answer:
w = 6
Step-by-step explanation:
11w - 9 - 7w = 15
4w = 15 + 9
w = 24/4
w = 6
Answer:
2.899
Step-by-step explanation:
Given that:
![f' (x) =3 tan ^{-1} (x^2 -3x +2)](https://tex.z-dn.net/?f=f%27%20%28x%29%20%3D3%20tan%20%5E%7B-1%7D%20%28x%5E2%20-3x%20%2B2%29)
![\text{applying integration on both sides with respect to x}](https://tex.z-dn.net/?f=%5Ctext%7Bapplying%20integration%20on%20both%20sides%20with%20respect%20to%20x%7D)
![\int \limits ^{3}_{1}} f'(x) \ dx = \int ^3_1 3tan ^{-1} (x^2 -3x+2) \ dx](https://tex.z-dn.net/?f=%5Cint%20%5Climits%20%5E%7B3%7D_%7B1%7D%7D%20f%27%28x%29%20%5C%20dx%20%3D%20%5Cint%20%5E3_1%203tan%20%5E%7B-1%7D%20%28x%5E2%20-3x%2B2%29%20%5C%20dx)
![f(3)-f(1)= 3 \int ^3_1 3tan ^{-1} (x^2 -3x+2) \ dx](https://tex.z-dn.net/?f=f%283%29-f%281%29%3D%203%20%5Cint%20%5E3_1%203tan%20%5E%7B-1%7D%20%28x%5E2%20-3x%2B2%29%20%5C%20dx)
![f(3) = \dfrac{\pi}{2}+3\int^{3}_{1} tan^{-1} (x^2 -3x+2)dx ---(1)](https://tex.z-dn.net/?f=f%283%29%20%3D%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%2B3%5Cint%5E%7B3%7D_%7B1%7D%20tan%5E%7B-1%7D%20%28x%5E2%20-3x%2B2%29dx%20---%281%29)
![\text{consider } \ \ 3\int^{3}_{1} tan^{-1} (x^2 -3x+2)dx](https://tex.z-dn.net/?f=%5Ctext%7Bconsider%20%7D%20%20%5C%20%20%5C%203%5Cint%5E%7B3%7D_%7B1%7D%20tan%5E%7B-1%7D%20%28x%5E2%20-3x%2B2%29dx)
![h = \dfrac{b-a}{n}](https://tex.z-dn.net/?f=h%20%3D%20%5Cdfrac%7Bb-a%7D%7Bn%7D)
![where; n = 10 , a =1, b= 3](https://tex.z-dn.net/?f=where%3B%20n%20%3D%2010%20%2C%20a%20%3D1%2C%20b%3D%203)
![h = \dfrac{3-1}{10}](https://tex.z-dn.net/?f=h%20%3D%20%5Cdfrac%7B3-1%7D%7B10%7D)
![h = \dfrac{2}{10}](https://tex.z-dn.net/?f=h%20%3D%20%5Cdfrac%7B2%7D%7B10%7D)
![h = 0.2](https://tex.z-dn.net/?f=h%20%3D%200.2)
![\text{The value of x and corresponding } y = 3tan^{-1}(x^2-3x+2) \ are:](https://tex.z-dn.net/?f=%5Ctext%7BThe%20value%20of%20x%20and%20corresponding%20%7D%20y%20%3D%203tan%5E%7B-1%7D%28x%5E2-3x%2B2%29%20%5C%20are%3A)
x 1 1.2 1.4 1.6 1.8 2 2.2 2.4 2.6 2.8 3
y f(0) f(1.2) f(1.4) f(1.6) f(1.8) f(2.0) f(2.2) f(2.4) f(2.6) f(2.8) f(3)
By simpson's rule:
![\int \limits ^3_1 \ 3 tan^{-1} (x^2-3x+2) dx \simeq \dfrac{h}{3}(y_o+y_{10}) +4(y_1+y_3+y_5+y_7+y_9)+2(y_2+y_4+y_6+y_8)]](https://tex.z-dn.net/?f=%5Cint%20%5Climits%20%5E3_1%20%5C%203%20tan%5E%7B-1%7D%20%28x%5E2-3x%2B2%29%20dx%20%5Csimeq%20%5Cdfrac%7Bh%7D%7B3%7D%28y_o%2By_%7B10%7D%29%20%2B4%28y_1%2By_3%2By_5%2By_7%2By_9%29%2B2%28y_2%2By_4%2By_6%2By_8%29%5D)
![=\dfrac{0.2}{3}\Big[(0+3.3214)+(-1.9039+2.8265+1.4133+6.1259+11.5657)+2(-1.4133-0.9519+1.4133+4.5899)\Big]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B0.2%7D%7B3%7D%5CBig%5B%280%2B3.3214%29%2B%28-1.9039%2B2.8265%2B1.4133%2B6.1259%2B11.5657%29%2B2%28-1.4133-0.9519%2B1.4133%2B4.5899%29%5CBig%5D)
![= 1.32804](https://tex.z-dn.net/?f=%3D%201.32804)
![\text{From}; f(3) = \dfrac{\pi}{2}+1.32804 \\ \\ f(3) = 2.89883633 \\ \\ \mathbf{f(3) \simeq 2.899}](https://tex.z-dn.net/?f=%5Ctext%7BFrom%7D%3B%20f%283%29%20%3D%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%2B1.32804%20%5C%5C%20%5C%5C%20f%283%29%20%3D%202.89883633%20%5C%5C%20%5C%5C%20%5Cmathbf%7Bf%283%29%20%5Csimeq%202.899%7D)
Dilation only changes size, since it makes a shape bigger or smaller. So I think you would just leave out the one saying that it has the same size.
Answer:
Snake who just put on a pair of socks.
Step-by-step explanation:
It looks like you're just missing two letters, p and s.
I hope this helped :)