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Aleksandr-060686 [28]
3 years ago
14

Help Fast!!!!!!

Mathematics
1 answer:
elixir [45]3 years ago
3 0

The formula for the area of a circle is A = πr^2

Since we know the length of the square is 7cm and the circle fills the full length, 7cm is the diameter.

To get the radius you divide the diameter by 2.

7/2 = 3.5

So, your radius is 3.5.

Now your formula looks like this: A = π(3.5)^2

Next you would square 3.5 because (3.5)^2 means to multiply 3.5 by 3.5

3.5^2 = 12.25

Now, you just multiply 12.25 by the approximate version of pi, which is 3.14.

12.25*3.14 = 38.465

Now, that you have the area of the circle, you subtract it from the area of the square.

If you already haven't figured out the area of the square it is 49 cm.

This is because the formula for the area of a square is A = bh or A = lw

Since the length (l) or base (b) is 7, we know that the other sides are 7 because squares have equal sides.

So now we subtract 38.465 from 49 and we get 10.535 which rounds to 10.54

So, your final answer is D. 10.54 cm^2

Hope this helps!

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1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
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Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
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