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mojhsa [17]
3 years ago
5

Maylin is mailing a package that has the

Mathematics
1 answer:
yarga [219]3 years ago
3 0

Answer:

V=378 inch³

Step-by-step explanation:

The package is in the shape of a cuboid. The volume of a cuboid is given by :

V = lbh

l=length, b=breadth and h=height

Area of base = 54 inch²

Height of box, h = 7 in

It means that, volume of the package is :

V = 54 × 7

V=378 inch³

So, the volume of the package is 378 inch³.

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the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
 bh=124x2
 bh=248

 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

 Base=b/2
 Height=3h

 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

 A'=bh/2

 (A' is the new area)

 A'=(b/2)(3)/2
 A'=3bh/4

 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
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3 0
3 years ago
A l-meter steel rod is bent into a rectangle so that its length exceeds quadruple its width
Dmitry_Shevchenko [17]

Answer:

The dimensions of the newly formed rectangle is length is 41 cm and width is 9 cm.

Step-by-step explanation:

Given,

A 1 meter steel rod is bent into a rectangle.

That means the perimeter of the rectangle is 1 meter.

So, Perimeter = 1\ m=100\ cm

Let the width of the rectangle be 'x'.

Now According to question, length exceeds quadruple its width by 5 cm.

Hence framing the above sentence in equation form, we get;

Length=4x+5

Now we use the formula of  perimeter of rectangle,

Perimeter=2(Length+width)

On substituting the values, we get;

2(4x+5+x)=100\\\\(5x+5)=\frac{100}{2}\\\\5x+5=50\\\\5x=50-5\\\\5x=45\\\\x=\frac{45}{5}=9

Now, we substitute the value of x to get the value of length;

Length=4x+5=4\times9+5=36+5=41\ cm

Thus, Width=9 cm    Length=41 cm

Hence the dimensions of the newly formed rectangle is length is 41 cm and width is 9 cm.

6 0
3 years ago
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