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Answer:
The focus of the parabola is at the point (0, 2)
Step-by-step explanation:
Recall that the focus of a parabola resides at the same distance from the parabola's vertex, as the distance from the parabola's vertex to the directrix, and on the side of the curve's concavity. In fact this is a nice geometrical property of the parabola and the way it can be constructed base of its definition: "All those points on the lane whose distance to the focus equal the distance to the directrix."
Then, the focus must be at a distance of two units from the vertex, (0,0), on in line with the parabola's axis of symmetry (x=0), and on the positive side of the y-axis (notice the directrix is on the negative side of the y-axis. So that puts the focus of this parabola at the point (0, 2)
100 is the correct answer
Hi!
<h3>Use the distribution property</h3>
1.4t — 0.4 * t - 0.4 * —3.1 = 5.8
1.4t — 0.4t - 1.24 = 5.8
<h3>Simplify</h3>
1t - 1.24 = 5.8
<h3>Add 1.24 to both sides</h3>
1t - 1.24 + 1.24 = 5.8 + 1.24
1t = 7.04
<u>t = 7.04</u>
<h2>The answer is t = 7.04</h2>
Hope this helps! :)
-Peredhel
Answer:
Step-by-step explanation:
Discussion
First draw FH
<FOH and <FGH share the end points of the chord FH
<FOH is a central angle.
<FGH touches the circumference of the circle in the on the same side of the point of angle <FOH is closest to
Therefore <FGH is 1/2 <FOH. That is always true of central angles and the smaller angle touching the circumference that <FOH points to
Conclusion
<FGH = 1/2 < FOH
58 = 1/2 <FOH
Therefore <FOH = 2 * 58 = 116
y = < FOH
Answer
y = 116
