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3 years ago

For this graph mark the statements that are true

Mathematics

1 answer:

Nitella [24]3 years ago

7 0

For the graph in the figure

we know that

the function is a quadratic equation ( vertical parabola) open up

The vertex is a minimum

the vertex is the point $(1,0)$

The domain x of the function is all real numbers-------> (-∞,∞)

The range is the interval--------> [0,∞)

$f(x)\geq 0$

therefore

Statements

A) The range is the set of all real numbers

Is false

B) The domain is the set of all real numbers

Is true

C) The domain is the set of all real numbers greater than or equal to zero

Is false

D) The range is the set of all real numbers greater than or equal to zero

Is true

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第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

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