Answer:
The width of the area model is equal to
Step-by-step explanation:
<u><em>The complete question is</em></u>
Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width
we know that
The area of a rectangular model is given by the formula
----> equation A
where
L is the length
W is the width
we have
Factor the expression
substitute the value of the Area in the equation A
In this problem
The greatest common factor of these terms is the length (L=5 units)
so
we can say that the width is equal to (2x^2-x+3)
therefore
The width of the area model is equal to
Answer: (-1,1,-3) + 7 x t x (3,-2,-8)/
Step-by-step explanation:
The parametric vector equation for the position of particle is given as:
We have P= (-1,1-3)
Q= (-4,4,5)
So PQ vector= (-1+4,1-3, -3-5)
PQ = (3,-2,-8)
Magnitude of this vector= 
Magnitude=
So unit vector= (3, -2, -8)/
Now the equation is as:
P + 7 x t x unit vector = (-1,1,-3) + 7 x t x (3,-2,-8)/
X
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Answer:
No Options
∠QOB=45º
Step-by-step explanation:
we have that: point O=Incenter, sides S, Q, R they form right angles with the point O, angle OBC = 15º and angle OCR=30º, find angle QOB
we know that the sum of all the internal angles of a triangle is 180º, so
α =180-30-15-90=45º and β = 180-90-α → β = 180-90-45 =45º,
Finally β=∠QOB=45º
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