The ball's height <em>y</em> at time <em>t</em> is
<em>y</em> = (22.1 m/s) <em>t</em> - 1/2 <em>gt</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.
Solve for <em>t</em> when <em>y</em> = 10 m:
10 m = (22.1 m/s) <em>t</em> - 1/2 <em>gt</em> ²
→ <em>t</em> = 0.510 s or <em>t</em> = 4.00 s
The first time refers to when the ball first reaches 10 m on its way up, so <em>t</em> = 4.00 s and the answer is A.