20 minutes on passing .....40 minutes on shooting
ratio of time spent on shooting to passing....
these are not hard, u just have to pay attention to the wording...
the ratio of shooting to passing is 40/20 which reduces to 2/1 or 2:1 or
2 to 1 <===
but if it would have asked for passing to shooting, it would have been :
20/40 which reduces to 1/2 or 1:2 or 1 to 2
so ur answer is 2/1 or 2:1 or 2 to 1
Answer:
see explanation
Step-by-step explanation:
The figure shown has one pair of parallel sides and is a trapezium
The area (A) of a trapezium is calculated using
A =
h(a + b)
where h is the height and a, b the length of the parallel sides
here h = 2w, a = w + 3 and b = 4w - 2, hence
A =
× 2w(w + 3 + 4w - 2)
= w(5w + 1) = 5w² + w
Macro can finish the puzzle in 3 hours. We can say that her speed for working is 1/3 or 1/3 puzzle per hour.
Now if they work together, this turns into 1 puzzle per hour.
That must mean that Cliff would be doing the other 2/3 of the puzzle while Macro does his 1/3 in that hour. If Cliff has a speed of doing them 2/3 per hour. Then it would take 1 and a half hour to finish 1 whole puzzle.
Let the price of a ticket be originally T dollars, and the number of clients be N.
let the price decrease by x 3-dollars.
"there is an average increase of 4 people for every $3 decrease on the price of the ticket."
means:
if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3
if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3
So if the price is decrease by x-3 dollars:
N becomes N+4x, and T becomes T-3x
"A circus owner sells an average of 340 tickets when the price of a ticket is $75."
In this case N=340, and T=75$
If the owner does not change the price ticket, x=0, the revenue is 340*75,
If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,
If R is the function of the revenue depending on x, then
R(x)=(340+4x)(75-3x) dollars
Answer: R(x)=(340+4x)(75-3x) dollars
Factor the coefficients:
-12=(-1)(3)(2^2)
-9=(-1)(3^2)
3=3
The greatest common factor (GCF) is 3
Next we find the GCF for the variable x.
x^4
x^3
x^2
The GCF is x^2.
Next GCF for variable y.
y
y^2
y^3
the GCF is y
Therefore the GCF is 3x^2y
To factor this out, we need to divide each term by the GCF,
(3x^2y)(−12x4y/(3x^2y) − 9x3y2/(3x^2y) + 3x2y3/(3x^2y) )
=(3x^2y)(-4x^2-3xy+y^2)
if we wish, we can factor further:
(3x^2y)(y-4x)(x+y)