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solniwko [45]
3 years ago
12

Question 3 of 10 Which of the following best describes the graph below? +2 54 -3 -2 -1 1 O A. It is a one-to-one function. O B.

It is a function, but it is not one-to-one. O C. It is not a function. D. It is a many-to-one function.​

Mathematics
2 answers:
denis23 [38]3 years ago
7 0

Answer: one to one function

Step-by-step explanation:

Kruka [31]3 years ago
4 0

Answer:

It is a one-to-one function

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How many towers can be built using 257 blocks
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Explanation:

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2 years ago
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3 years ago
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What the geometric mean between 12 and 18
MAVERICK [17]

Answer: 14.7

Step-by-step explanation:

Data : 12,18    

Total Number of Values, N = 2

Step 1 : Find 1 / N

1 / N = 1 / 2 = 0.5

Step 2 : Find mean

GM = ( 12 * 18 )^ 0.5

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4 0
3 years ago
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The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

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3 years ago
The area of a rectangular garden is 5828 m
evablogger [386]

Answer:

The length of the garden is 94 m.

Step-by-step explanation:

you do 5828 m. divided by 62m. and that is how you get your answer of 94 m.

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