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Tatiana [17]
2 years ago
8

For brainiest:):):):):):)

Mathematics
1 answer:
dedylja [7]2 years ago
3 0

Answer:

4=12%

5=7

6=12.25

7=82%

8=15.36

Step-by-step explanation:

youre welcome

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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
4+8÷2-2×3 what would we do first a 4+8 b8÷2 c2-2 d2×3​
murzikaleks [220]

Answer:

multiplication, so d, 2 x 3

Step-by-step explanation:

remember... PEMDAS!!

3 0
2 years ago
1/6 * 3/4<br> could be answers <br> 3/10<br> 1/6<br> 1/8 <br> 4/10
Dominik [7]

Answer:

it's a sooooooo it's the first one

5 0
3 years ago
Read 2 more answers
What is the union sets M= (1,7,10,11,15) and N=(5,15)?
katen-ka-za [31]

Answer: <em>(1,5,7,10,11,15)</em>

To get the union of two sets of numbers, all you do is combine the numbers from least to greatest. If a number repeats in the 2 sets, you only put it once.

7 0
3 years ago
Read 2 more answers
3n+4 first the 7 terms
kiruha [24]

Answer:

4, 7, 10, 13, 16, 19, 22

Step-by-step explanation:

Not sure if there is more to this question but here is what I assume:

We want to find the first 7 terms of this equation given 3n+4

Assuming we are starting at 0 we plug 0 in for n.

3(0) + 4 → 4

So our first answer is 4

We continue by pugging in the next numbers after that to get to the first 7 terms

3(1) + 4 → 7

3(2) + 4 → 10

3(3) + 4 → 13

3(4) + 4 → 16

3(5) + 4 → 19

3(6) + 4 → 22

5 0
3 years ago
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