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2 years ago

5

The area of a circle is equal to 1 dm2. Find the radius of the circle.

1 answer:

lisov135 [29]2 years ago

7 0

Answer:

2000

Step-by-step explanation:

1 dm =1000

2dm =?

2dm x 1000

1dm

2000

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THIS IS A MATH QUESTION ON DIFFERENT TYPES OF TRIANGLES TY :)

weqwewe [10]

1. This triangle is scalene.

2. This triangle is isosceles. Two angles are equal.

3. This triangle is equilateral, all sides are equal.

4. This triangle is equilateral, all angles are equal.

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2 years ago

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The globe used in social studies class has a diameter of 42 centimeters, What is its volume

Leni [432]

Answer:

Step-by-step explanation: pi r^2

so 42/2 equals 21 radius

volume=22/7 x 21^2

v=1385

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2 years ago

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The graph of a line has a slope of -3 and passes through the point (-6,-4).

prohojiy [21]

Answer:

(A) y+4=-3(x+6)

Step-by-step explanation:

The point-slope form of the equation of a line whose slope is m and passes through the point $(x_1, y_1)$ is: $y-y_1=m(x-x_1)$

Given the point: $(x_1, y_1)=(-6,-4)$

Slope, m=-3

$x_1=-6\\y_1=-4$

Substituting these values into: $y-y_1=m(x-x_1)$ , we obtain the point slope form of the equation:

$y-(-4)=-3(x-(-6))\\\\y+4=-3(x+6)$

The correct option is A.

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3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

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1 year ago

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Zigmanuir [339]

10n - 20p + 20

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2 years ago

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