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topjm [15]
3 years ago
12

Combine like terms and simplify the expression. 9x + 6 -3

Mathematics
2 answers:
faust18 [17]3 years ago
7 0

Answer:

9x+3

Step-by-step explanation:

The only thing you have to do is subtract 3 from 6!

stira [4]3 years ago
5 0

Answer:

9x+6

Step-by-step explanation:

6-3=3

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Write the equation of the line that is parallel to the line and through the given point y=-2x+1 point (0,5)
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Answer:

y = -2x+5

Step-by-step explanation:

y = -2x+1 is in the form y= mx+b where m is the slope and b is the y intercept

-2 is the slope

Parallel lines have the same slope so our new line will have the same slope

y = -2x+b

The point given is the y intercept (value when x is zero)

b = 5

y = -2x+5

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3 years ago
Find the next number in the number pattern 192,96,48,24
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Step-by-step explanation:

8 0
3 years ago
Carlotta handpaints T-shirts and sells them to her friends. She uses the equations below to determine her costs and the amount o
spayn [35]
Profit = Income - cost
Profit = 10s - (28 + 3s) = 10s - 28 -3s = 7s - 28.

Profit = 0

0 = 7s - 28

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s = 4. This is the breakeven point.

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8 0
3 years ago
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For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
Rus_ich [418]

To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

x\frac{3}{2} is the required solution of the given inequality.

5 0
4 years ago
Read 2 more answers
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